Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Maximum area of rectangular park that can be enclosed using 5 feet long concrete barriers is equals to 40,000 square feet.
What is rectangle?
" Rectangle is defined as quadrilateral whose opposite sides are parallel and congruent with one of the angle equals to 90°."
According to the question,
Length of the concrete barrier = 5feet
Number of barriers = 160
Total length of barriers = 160 × 5
= 800 feet
'l' represents the length of the rectangular park
'w' represents the width of the rectangular park
'A' represents the area of the rectangular park
Perimeter of the Rectangular park = 2 ( length + width)
⇒800 = 2(l + w)
⇒ l + w = 400
⇒ w = 400 - l
Area of the rectangular park = length × width
⇒ A = l × ( 400 - l )
⇒A = 400l - l²
⇒[tex]\frac{dA }{dl} = 400 -2l[/tex]
⇒ [tex]\frac{d^{2} A}{dl^{2} }=-2 < 0[/tex]
Therefore , maximum function.
[tex]\frac{dA }{dl} =0[/tex]
⇒[tex]400 -2l =0[/tex]
⇒[tex]l= 200[/tex]
and
[tex]w = 200[/tex]
Maximum area that can be enclosed = 200 × 200
= 40,000 square feet.
Hence, maximum area of rectangular park that can be enclosed using 5 feet long concrete barriers is equals to 40,000 square feet.
Learn more about rectangle here
https://brainly.com/question/15019502
#SPJ3
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.