Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

simplify the following:
a) ((w^-5)/(w^-9))^1/2
b) (m^6)^-2/3
c) (3x^-4y^5)/((2x^3y^-7))^-2

Sagot :

brookegallagher
a. [tex] (\frac{w^{-5}}{w^{-9} })^{ \frac{1}{2} } \\ ( \frac{w^{9} }{w^{5} })^{ \frac{1}{2} } \\ (w^{9-5})^{ \frac{1}{2} } \\ (w^{4})^{ \frac{1}{2} } \\ \sqrt{w^{4} } \\ w^{2} [/tex]
b.[tex](m^{6})^{ \frac{-2}{3} } \\ (\frac{1}{m^{6} })^{\frac{2}{3} } \\ \frac{ \sqrt[3]{1^{2} } }{ \sqrt[3]{m^{6} }^{2} } \\ \frac{ \sqrt[3]{1} }{m^{2*2} } \\ \frac{1}{m^{4} } [/tex]
Hope this helps!
Panoyin
Problem A
[tex](\frac{w^{-5}}{w^{-9}})^{{\frac{1}{2}} [/tex] = [tex](\frac{w^{9}}{w^{5}})^{{\frac{1}{2}} [/tex] = [tex](w^{4})^{{\frac{1}{2}} [/tex] = [tex]\sqrt[2]{w^{4}} [/tex] = [tex]w^{2}[/tex]

Problem B
[tex](m^{6})^{-\frac{2}{3}} [/tex] = [tex]\frac{1}{(m^{6})^{\frac{2}{3}}}[/tex] = [tex]\frac{1}{\sqrt[3]{(m^{6})^{2}}} [/tex] = [tex]\frac{1}{\sqrt[3]{m^{12}}} [/tex] = [tex]\frac{1}{m^{4}} [/tex]

Problem C
[tex](\frac{3x^{-4}y^{5}}{2x^{3}y^{-7}})^{-2} [/tex] = [tex](\frac{3y^{12}}{2x^{7}})^{-2} [/tex] = [tex]\frac{(3y^{12})^{-2}}{(2x^{7})^{-2}} [/tex] = [tex]\frac{(2x^{7})^{2}}{(3y^{12})^{2-}} [/tex] = [tex]\frac{4x^{14}}{9y^{24}} [/tex]


Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.