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Determine the inverse function of f(x)=[tex] \sqrt{4x-1} [/tex]

Sagot :

[tex]f(x)=\sqrt{4x-1}\\ y=\sqrt{4x-1}\\ y^2=4x-1\\ 4x=y^2+1\\ x=\dfrac{y^2+1}{4}\\ f^{-1}(x)=\dfrac{x^2+1}{4}\\[/tex]