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HELP PLEASE

Which equation is graphed here?

A. y-3=-2/3(x+1)

B. y-4=-3/2(x+2)

C. y-1=-3/2(x+3)

D. y+1=-2/3(x+3)

HELP PLEASE Which Equation Is Graphed Here A Y323x1 B Y432x2 C Y132x3 D Y123x3 class=

Sagot :

B
it is a easy question. just find two points and find a good function
like these points: (0,1) .  (2, -2)

Answer:

Option B is correct.

[tex]y-4=-\frac{3}{2}(x+2)[/tex]

Step-by-step explanation:

Point slope form:

The equation of  straight line is given by:

[tex]y-y_1=m(x-x_1)[/tex] ......[1] where m is the slope and a point [tex](x_1, y_1)[/tex] lies on the coordinate plane

From the given graph:

Consider two points i.e,

(-2, 4) and (2, -2)

Calculate slope:

Slope(m) is given by;

[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]

Substitute the given points we have;

[tex]m = \frac{-2-4}{2-(-2)} = -\frac{6}{4} = -\frac{3}{2}[/tex]

Now, substitute the value of m and (-2, 4) in [1] we have;

[tex]y-4=-\frac{3}{2}(x-(-2))[/tex]

or

[tex]y-4=-\frac{3}{2}(x+2)[/tex]

Therefore, the equation is graphed here is [tex]y-4=-\frac{3}{2}(x+2)[/tex]





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