Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6

Sagot :

apsweetangel9
d: 1/3x-y+6, A(-9, 12)
md=-b/a=1/1/3=3, md=slope d

d`: y-yA=md(x-xA)
     y-12=3(x+9)
     y-12=3x+27
=> d`: 3x-y+15=0
belcatya
y=kx+b
line is perpendicular y=1/3x+6⇒ k=-[tex] \frac{1}{ \frac{1}{3} } [/tex]=-3

 so line y=-3x+a
 this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture to test solutions in the application


View image belcatya
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.