Angelv00
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HELP PLEASE
A bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

What is the probability that the golf ball he selects is white or pink?

A.5/54

B.13/5

C.5/13

D.13/18

Sagot :

your answer equals D

Answer:  The correct option is (D) [tex]\dfrac{13}{18}.[/tex]

Step-by-step explanation:  Given that a bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

We are to find the probability that the golf ball he selects is white or pink.

Let, 'A' denotes the event that the golf ball that Jason selects is either white or pink.

Then, n(A) = 10 + 3 = 13.

Let, 'S' denotes the sample space for the experiment.

Then, n(S) = 10 + 3 + 5 = 18.

Therefore, the probability that the probability that the golf ball Jason selects is white or pink is given by

[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{13}{18}.[/tex]

Thus, the required probability is [tex]\dfrac{13}{18}.[/tex]

Option (D) is correct.

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