Arioue123
Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Solving by completing the square
X square+4x-4=0

Sagot :

naǫ
[tex]x^2+4x-4=0 \\ x^2+4x+4-4-4=0 \\ (x+2)^2-8=0 \\ (x+2)^2=8 \\ x+2=\pm \sqrt{8} \\ x+2=\pm \sqrt{4 \times 2} \\ x+2=\pm2\sqrt{2} \\ x+2=-2\sqrt{2} \ \lor \ x+2=2\sqrt{2} \\ x=-2\sqrt{2}-2 \ \lor \ x=2\sqrt{2}-2 \\ \boxed{x=-2\sqrt{2}-2 \hbox{ or } x=2\sqrt{2}-2}[/tex]
konrad509
[tex]x^2+4x-4=0 \\ x^2+4x+4-8=0\\ (x+2)^2=8\\ x+2=-\sqrt8 \vee x+2=\sqrt8\\ x=-2-2\sqrt2 \vee x=-2+2\sqrt2[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.