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Sagot :
V=Vo+at (velocity=initial velocity plus acceleration multiplied by time)
40m/s=25m/s+a(3s)
-25 -25
15m/s=a(3s) divide by 3s on both sides
5m/s^2=a
40m/s=25m/s+a(3s)
-25 -25
15m/s=a(3s) divide by 3s on both sides
5m/s^2=a
Explanation:
It is given that,
Initial velocity of the truck, u = 25 m/s
Final speed of the truck, v = 40 m/s
Time taken, t = 3 s
We need to find the acceleration of the truck. It can be calculated using formula as :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{40-25}{3}[/tex]
[tex]a=5\ m/s^2[/tex]
So, the acceleration of the truck is 5 meter per second square. Hence, this is the required solution.
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