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Sagot :
Answer:
F = 645 N
Explanation:
For equilibrium in vertical direction we can make force balance
so we will have
[tex]F_y + Tsin32 = mg[/tex]
[tex]F_y + 710 sin32 = (62\times 9.8)[/tex]
[tex]F_y = 607.6 - 376.2 [/tex]
[tex]F_y = 231.3 N[/tex]
Now for horizontal equilibrium we know that
[tex]F_x = Tcos32[/tex]
[tex]F_x = 710cos32[/tex]
[tex]F_x = 602.11 N[/tex]
now we have net force due to wall given as
[tex]F = \sqrt{F_x^2 + F_y^2}[/tex]
[tex]F = \sqrt{231.3^2 + 602.11^2}[/tex]
[tex]F = 645 N[/tex]
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