Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The equation for circle is 28g + 16f =260
and the equation of tangent to this circle is y = [tex]\frac{6}{12}[/tex] x +29
a) the main equation of circle is ax + by +2gx+ 2fy +c =0 --------- (1)
Now,
putting the points (0,0) , (0,8) and (6,12) one by one, we get,
For the point (0,0), we get:
c =o ----------------------------- (2)
For the point (6,12), we get:
6x +12y + c = (6)² + (12)²
⇒ 6x +12y +c = 36 +144
⇒ 6x +12y +c = 180 --------------------------- (3)
For the point (0,8), we get,
8y + c = 64 ----------------------------- (4)
putting c=0,
8y +0 = 64
⇒ y =64/8
⇒ y = 8
Putting c=0 and y =8, we get,
6x + 12×8 +0 = 180
⇒ 6x + 96 =180
⇒ 6x = 84
⇒ x = 14
Putting all the values in equation (1), we get:
(14)² + (8)² +28g +16g + 0 = 0
⇒ 196 + 64 + 28g +16f =0
⇒ 28g + 16f = 260
b) As we know the tangent from the circle:
y = mx + c
⇒ 8 = -12/6 × 14 +c
⇒ c = 29
Therefore, the equation of the tangent is y = [tex]\frac{6}{12}[/tex]x + 29
Learn more about Tangent :
https://brainly.com/question/19424752
#SPJ4
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
