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What is the slope of a line perpendicular to the line whose equation is 15x-18y=-486.

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The slope of the line which is perpendicular to the given line is (-6/5).

Describe the negative reciprocal.

The negative reciprocal of a number, let's say "n," is "- (1/n).

We are aware of a line's equation in slope intercept form, y = mx + b, as well as the fact that perpendicular lines have slopes that are reciprocal to each other's negative values.

The slope intercept form of the line 15x - 18y = -486 can be expressed as,

-18y = -15x - 486.

- y = (-15/18)x - (486/18).

- y = (-5/6)x - 27.

y = (5/6)x + 27.

The slope of the supplied line is (5/6), making the perpendicular line's slope (-6/5).

learn more about slope here :

brainly.com/question/3605446

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