The genotype of the blue-eyed man is bb if B is the allele for brown eyes and b is blue. His wife must be a Bb heterozygote, meaning she must have both the B allele (since she has brown eyes) and the b gene from her blue-eyed mother (whose genotype was bb).
Blue eye colour is subordinate to brown eye colour. As a result, it is possible that both of the parents of a child with blue eyes, who has brown eyes, have a heterozygous genotype Bb. Therefore, it is evident from the square below that there is a 25% chance of having a blue-eyed (bb) child.
He will have brown eyes and the genotype Bb. The blue-eyed woman will have genotype bb. As a result, their progeny may have the genotypes Bb and bb.
A monohybrid cross yields a genotypic ratio of 1:2:1 and a phenotypic ratio of 3:1 (dominant to recessive)
Thus, if B is the allele for brown eyes and b is blue, we can say that the genotype of the blue-eyed man is bb. His spouse must be a Bb heterozygote, that is, she must inherit her mother's blue eyes' B allele as well as the b gene.
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