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Sagot :
The period of the oscillation when the object is given a slight push and executes is 0.85 seconds.
What time of year is spring?
In spring-mass systems, the time period of the spring is utilized to calculate the oscillation of a system that performs simple harmonic motion. The following formula may be used to determine the length of the spring.
[tex]T=2 \pi \sqrt{\frac{m}{k} }[/tex]
The spring-mass (m) and the spring constant (k) are both present in this equation. Because the spring force balances the gravitational pull. The above formula may thus alternatively be expressed as,
[tex]T=2 \pi \sqrt{\frac{x}{g} }[/tex]
In this case, x denotes the spring's separation from the equilibrium point.
An object of unknown mass m is hung from a vertical spring of unknown spring constant k, and the thing is observed to be at rest when the spring has extended by 18 cm or 0.18 m
[tex]T=2\pi \sqrt{\frac{0.18}{9.81} }[/tex]
T= 0.85 seconds
Learn more about the time period here:
https://brainly.com/question/23938295
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