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assume the magnetic susceptibility data were measured for the iron (ii) compounds given below and that the data reveals only one of them is low-spin. which of the compounds will be low-spin? hint: consult your spectrochemical series. (nh4)2[fe(h2o)6](so4)2 na4[fe(co3)3] k4[fe(cn)6] k4[fecl6] k3[fe(oxalate)3]

Sagot :

The low-spin compound in this set of compounds is K₄[Fe(CN)₆].

The spectrochemical series is a list of ligands ranked in order of their ability to stabilize low-spin complexes. According to the series, CN⁻ is the strongest low-spin ligand, followed by Cl⁻, CO₃⁻, and oxalate. Therefore, the compound that is most likely to be low-spin is K₄[Fe(CN)₆]. The other compounds on the list are more likely to be high-spin because the ligands they contain are weaker than CN⁻ at stabilizing low-spin complexes.

Since it is near the high-spin end of the spectrochemical series (i.e. it has a high coordination number and a high oxidation state). The other compounds in the set all have lower coordination numbers and/or lower oxidation states, so they are more likely to be high-spin.

In general, the more electrons an atom has in its outer shell, the more likely it is to be low-spin. Therefore, compounds with higher oxidation states and higher coordination numbers are more likely to be low-spin.

Hence, K₄[Fe(CN)₆] has a low spin with a strong field ligand in the spectrochemical series.

To know more about the spectrochemical series, click below:

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