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Sagot :
The vibration amplitude of a spring with a constant of 20 N/m which has a speed of 1.5 m/s with a mass of 0.50 kg which is associated = 0.237 m.
Oscillation Energy
When an object oscillates on a spring, the kinetic energy and potential energy of the mass-spring system change with time.
The total energy (the kinetic energy + potential energy) is constant.
The kinetic energy of an object moving with speed v is:
½ mv².
The potential energy of a spring with a constant k is:
= ½ kx².
The total energy = ½ kx² + ½ mv² = ½ kA².
The total energy equation gives the general property of simple harmonic oscillations which is directly proportional to the square of the amplitude.
And, we have:
m = 0.50 kg
k = 20 N/m
v = 1.5 m/s
Remember, the total energy = ½ kA².
So,
A² = (m)(v)² / k
= (0.50) (1.5)² / 20
= 0.05625
A = [tex]\sqrt{0.05625}[/tex]
= 0.237 m
Learn more about oscillation energy here: https://brainly.com/question/28543819
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