Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
B= ½ [U₀I/2a-U₀I/2b) out= U₀I/4 [1/a – 1/b] out = B
The magnetic field from the circle of a wire is B = U₀I/2R
Therefore there are 2 half circles. The out circle makes the B field into the page at the point P and the inner circle is making the field out of the page. To easily see this, the best thing to use is an RHR. Thus, subtraction is applied. The two straight wire lengths are not contributing to this filed because they seem to be running into/out of P. This means that r and I are parallel, thus the cross-product in Biot-Savart calculation will got to zero.
The answer be written down (this is after discovering that there are 2 half circles):
B= ½ [U₀I/2a-U₀I/2b) out= U₀I/4 [1/a – 1/b] out = B
Read more from https://brainly.com/question/29780731?
#SPJF
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
