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Find the dimensions of a rectangle with perimeter 76 m whose area is as large as possible. (If both values are the same number, enter it into both blanks.)

Sagot :

The dimensions of a rectangle are 19m.

Here we have to find the dimensions of a rectangle.

Data given:

Perimeter = 76m

The formula for the perimeter of the rectangle:

perimeter = 2( length + breadth)

So,

76 = 2 ( l+b)

l + b = 38

l = 38 -b

The formula for the area of the rectangle:

Area = length × breadth

A =( 38-b)×b

  = 38b - b²

At maximum point:

dA/ dw = 38 - 2b

38 - 2b = 0

b = 19

Therefore the dimension is 19m.

To know more about the rectangle refer to the link given below:

https://brainly.com/question/25292087

#SPJ4

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