Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The sample standard deviations of the data set 2, 3, 5, 6, 7 rounded up to 2 decimal spaces is 2.07.
The term "standard deviation" refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed. Think about the following data: 2, 1, 3, 2, 4.
The average and the total square of the observations' departures from the mean will be 2.4 and 5.2, respectively. This means that (5.2/5) = 1.01 will be the standard deviation. The standard deviation reveals the degree of data skewedness. It gauges how far away from the mean each observed value is. Approximately 95% of values in any distribution will be within two standard deviations of the mean.
Number of data points (n)=5
Mean (x)= (2+3+5+6+7)/5= 4.6
Here x = 2, 3, 5, 6, 7
(x-x) = -2.6, -1.6, 0.4, 1.4, 2.4
[tex](x-X)^{2}[/tex] = 6.76, 2.56, 0.16, 1.96, 5.76
∑[tex](x-X)^{2}[/tex] = 17.2
Sample standard deviation :
[tex]\sqrt{\frac{(x-X)^{2}}{n-1} } \\\\\sqrt{\frac{17.2}{4} } \\\\[/tex]
= 2.07
To know more about Sample standard deviation, visit: https://brainly.com/question/16934954
#SPJ4
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
