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Sagot :
- work is done on ball by its weight; Wg = 27 J
- gravitational potential energy; Ug0 = +36 J
- gravitational potential energy relative to the ground; Ugf = +8.8J
- change (PEf- PE0) = -27 J.
Explain the term gravitational potential energy?
- The energy that an object has or acquires when its position changes as a result of being in a gravitational field is known as gravitational potential energy.
- Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
The work that gravity does;
W = F.S = mgΔh
In light of the fact that gravity points downward and that displacement is also downward, their angle is 0 and their cosine 1, respectively.
W = mgΔh
g = 9.8 m/s²
Δh = 4.6 m
m = 0.60 kg
W = 0.60 x 9.80 x 4.6
W = 2.7 J
The source of gravitational potential energy in relation to the ground is;
U = mgh
The release point therefore
Ug = mgh(0)
U0 = 0.60 x 9.8 x 6.1
U0 = 35.87 J
At the point of release
U(gf) = mgh(f)
U(gf) = 0.60 x 9.80 x 1.5
U(gf) = 8.820 J
Gravitational potential energy changes are;
ΔU(g) = U(gf) - U0
ΔU(g) = 8.820 J - 35.87 J
ΔU(g) = -27.05 J
Result, we can see that the work done through gravity is the opposite of how the gravitational potential energy has changed.
To know more about the gravitational potential energy, here
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