Answer:
Centripetal acceleration: [tex]1250\; {\rm m\cdot s^{-2}}[/tex].
Resultant force on the object should be [tex]12500\; {\rm N}[/tex].
(Assuming that the speed of the object is [tex]50\; {\rm m\cdot s^{-1}}[/tex].)
Explanation:
For an object that travels along a circle path of radius [tex]r[/tex] at a speed of [tex]v[/tex], (centripetal) acceleration will be [tex]a = (v^{2} / r)[/tex].
In this example, speed is [tex]v = 50\; {\rm m\cdot s^{-1}}[/tex] while the radius of the circular path is [tex]r = 2\; {\rm m}[/tex]. The (centripetal) acceleration of this object will be:
[tex]\begin{aligned}a &= \frac{v^{2}}{r} \\ &= \frac{(50\; {\rm m\cdot s^{-1}})^{2}}{(2\; {\rm m})} \\ &= 1250\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
For an object of mass [tex]m[/tex], the resultant force to achieve acceleration [tex]a[/tex] is [tex]F(\text{net}) = m\, a[/tex]. In this example, [tex]m = 10\; {\rm kg}[/tex] while [tex]a = 1250\; {\rm m\cdot s^{-2}}[/tex]. The required resultant force will be:
[tex]\begin{aligned}F(\text{net}) &= m\, a \\ &= (10\; {\rm kg})\, (1250\; {\rm m\cdot s^{-2}}) \\ &= 12500\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 12500\; {\rm N} \end{aligned}[/tex].
