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a plumber cuts 2 3/4 feet from pipe. The pipe is now 13 1/4 feet long. Write and solve an equation of to determine the original length if the pipe

Sagot :

Answer:

x - 2 [tex]\frac{3}{4}[/tex] = 13 [tex]\frac{1}{4}[/tex]

x = 16

Step-by-step explanation:

x - 2 [tex]\frac{3}{4}[/tex] = 13 [tex]\frac{1}{4}[/tex]

x - [tex]\frac{11}{4}[/tex] = [tex]\frac{53}{4}[/tex]  Add [tex]\frac{11}{4}[/tex] to both sides

x = [tex]\frac{53}{4}[/tex] + [tex]\frac{11}{4}[/tex]

x = [tex]\frac{64}{4}[/tex]

x = 16

semsee45

Answer:

[tex]x-2 \frac{3}{4}=13 \frac{1}{4}[/tex]

(where x is the original length of the pipe).

Original length of the pipe = 16 feet

Step-by-step explanation:

Let x be the original length of the pipe.

Given a plumber cuts 2 3/4 feet from a pipe and now has a pipe that is 13 1/4 feet long, the equation that models this is:

[tex]\boxed{ x-2 \frac{3}{4}=13 \frac{1}{4}}[/tex]

To determine the length of the original pipe, solve the equation for x.

Add 2 3/4 to both sides of the equation:

[tex]\implies x-2 \frac{3}{4}+2 \frac{3}{4}=13 \frac{1}{4}}+2 \frac{3}{4}[/tex]

[tex]\implies x=13 \frac{1}{4}}+2 \frac{3}{4}[/tex]

When adding mixed numbers, partition the mixed numbers into fractions and whole numbers, and add them separately:

[tex]\implies x=13 +\dfrac{1}{4}}+2 +\dfrac{3}{4}[/tex]

[tex]\implies x=13 +2 +\dfrac{1}{4}}+\dfrac{3}{4}[/tex]

[tex]\implies x=15 +\dfrac{1+3}{4}[/tex]

[tex]\implies x=15 +\dfrac{4}{4}[/tex]

[tex]\implies x=15 +1[/tex]

[tex]\implies x=16[/tex]

Therefore, the original length of the pipe was 16 feet.

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