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Sagot :
The probability of rolling a die 10 times and obtaining odd digit 8 or less of the rolls is 529/512 = 1.033
Let us call, getting an odd no. on a roll of die, Success.
The, clearly, the probability p of Success is 3/6 = 1/2.
Hence, q = 1 −p = 1/2
If, X = x denotes the no. of success in n trials, then, X is a
Binomial Random Variable, with parameters
n = 10, and, p = 1/2.
Binomial Random Variable:
This is a specific type of discrete random variable. A binomial random variable counts how often a particular event occurs in a fixed number of tries or trials. For a variable to be a binomial random variable, ALL of the following conditions must be met:
- There are a fixed number of trials (a fixed sample size).
- On each trial, the event of interest either occurs or does not.
- The probability of occurrence (or not) is the same on each trial.
- Trials are independent of one another.
Then, the Probability of x success out of n trials, i.e.,
P (X = x), is,
P (X = x) = p(x) =ⁿCₓ pˣ , qⁿ⁻ˣ, x = 0,1,2, ........, n
In our case,
P (X = x) = ¹⁰Cₓ (1/2)ˣ (1/2)¹⁰⁻ˣ ,x = 0,1,2,..., 10, i.e.,
P (X = x) = p(x) = ¹⁰Cₓ (1/2)¹⁰ = ¹⁰Cₓ /1024, x = 0, 1, ..., 10.
Hence,
The Required Probability = P( X< 8),
⇒ P (X = 0)+ P( X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) +P(X = 6) + P(X= 7) + P(X =8)
⇒ 1/1024 ( 1 + 10 + 45 + 120 +210 + 252 + 210 + 120 +90)
⇒ 1/1024 ×1058
⇒ 529 / 512
⇒ 1.033
Learn more about Probability:
https://brainly.com/question/9793303
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