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Sagot :
The density of a gas with a molar mass of 28.011gmol at 281 k and 1.90 atm is 2.30 g/l or grams per liter.
The formula for the ideal gas constant is PV= nRT
[tex]\frac{P}{RT}= \frac{n}{V}[/tex] = molarity
[tex]\frac{n}{V}[/tex] = molarity
Using M = molar mass to multiply both sides, we obtain
[tex]\frac{PM}{RT} = \frac{nM}{V}[/tex]
We can write [tex]\frac{PM}{RT}[/tex]= ρ.......equation (i)
since density, ρ = [tex]\frac{mass}{volume}[/tex] and
density, ρ= [tex]molarity*molar mass (\frac{nM}{V})[/tex]
After plugging in all the numbers in equation (i), we get
ρ= [tex]\frac{ 1.90*28.011}{281*0.082}[/tex]
ρ= [tex]\frac{522090}{2304200}[/tex]
ρ= 2.30 g/l.
To learn more about molar mass, refer:-
https://brainly.com/question/22997914
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