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Sagot :
The amount of heat released is -55 kJ which can be calculated using the number of moles and the enthalpy of vaporization.
At constant pressure, the amount of heat that is released or absorbed is identical to the enthalpy change.
It can be expressed as follows:
q= ΔHvap
Here, q represents the heat change and ΔHvap represents the enthalpy change.
The amount of heat released can be calculated as follows:
q= ΔHvap×n
q=(-220 kJ/mol)×0.25 mol
q=-55 kJ
Therefore, the amount of heat released is -55 kJ.
To learn more about heat check the link below:
https://brainly.com/question/13439286
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