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day weight (ounces) monday 23 22 23 24 tuesday 23 21 19 21 wednesday 20 19 20 21 thursday 18 19 20 19 friday 18 20 22 20 what is the mean of the sampling distribution of sample means when this process is in control?

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The value of the required mean of the sampling distribution of sample means is approx. 21 ounces when this process is in control.

Sample mean: The arithmetic mean of the values of the variables in the sample. If the samples are drawn from probability distributions with a common expected value, the sample mean is an estimate of that expected value.

Sample means for all days using formula,

Monday = (23+22+23+24)/4 = 23

Tuesday = (23+21+19+21)/4 = 21

Wednesday = (20+19+20+21)/4 = 20

Thursday = (18+19+20+19)/4 = 19

Friday = (18+20+22+20)/4 = 20

We have to calculate the mean of sampling distribution of sample means.

Mean of the sampling distribution of sample means = Sum of sample means of all days / Number of days

= (23+21+20+19+20)/5

= 20.6 = 21 ounces

Hence, the required mean is approx. 21 ounces.

To learn more about Sampling distribution of sample means , refer:

https://brainly.com/question/26952915

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