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Sagot :
The probability that at least one of the lights is defective is 0.2661 .
in the question ,
it is given that
the total number of bulbs in the pack of new light bulbs is (n) = 5
percent of bulb that did not work is = 6%
probability that lights did not work is (p) = 0.06
probability that lights work is (q) = 1 - 0.06 = 0.94
let x be the number of defective lights
So ,the probability that at least one of your lights is defective
is P(x ≥ 1) = 1 - P(x<1)
= 1 - P(x = 0)
By Binomial Probability
= 1 - ⁿCₓ*(p)ˣ*(q)ⁿ⁻ˣ
= 1 - ⁵C₀*(0.06)⁰*(0.94)⁵⁻⁰
= 1 - 1*1*(0.94)⁵ ...because ⁵C₀ = 1
= 1 - (0.94)⁵
= 1 - 0.7339
= 0.2661
Therefore , The probability that at least one of the lights is defective is 0.2661 .
The given question is incomplete , the complete question is
You purchased a five-pack of new light bulbs that were recalled because 6% of the lights did not work. What is the probability that at least one of your lights is defective ?
Learn more about Probability here
https://brainly.com/question/28788900
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