Answered

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Solve the system of 3 equations using substitution of eliminationx + 2y + 3z = 92x + 6y + 4z = 10x + 4y - z = -5

Sagot :

SOLUTIONS

[tex]\begin{gathered} x+2y+3z=9 \\ 2x+6y+4z=10 \\ x+4y-z=-5 \end{gathered}[/tex]

Therefore the solutions are

[tex]\begin{gathered} x=2 \\ y=-1 \\ z=3 \end{gathered}[/tex]

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