Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What is the average rate of change of f(x) = -10x³ + 7x² - 5x - 4 from x1 =-0.7 to x2=4.2? Please write your answer rounded to the nearest hundredth

Sagot :

Answer:

The average rate of change = -132.40

Explanation:

The given function is:

f(x) = -10x³ + 7x² - 5x - 4

At x₁ = -0.7

f(-0.7) = -10(-0.7)³ + 7(-0.7)² - 5(-0.7) - 4

f(-0.7) = 6.36

At x₂ = 4.2

f(4.2) = -10(4.2)³ + 7(4.2)² - 5(4.2) - 4

f(4.2) = -642.4

The average rate of change of f(x) is calculated as:

[tex]\begin{gathered} \frac{\triangle f(x)}{\triangle x}=\frac{f(x_2)-f(x_1)}{x_2-x_1} \\ \frac{△f(x)}{△x}=\frac{f(4.2)-f(-0.7)}{4.2-(-0.7)_{}} \\ \frac{△f(x)}{△x}=\frac{-642.4-6.36}{4.2+0.7_{}} \\ \frac{△f(x)}{△x}=\frac{-648.76}{4.9_{}} \\ \frac{△f(x)}{△x}=-132.40 \end{gathered}[/tex]

The average rate of change = -132.40

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.