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Given the following function find f(-1), f(0) and f(5) f(x)=2x+1f(x-1)=?

Sagot :

Solution:

Given the function:

[tex]f(x)=2x+1[/tex]

To find f(-1), f(0), and f(5), we substitute the values of -1, 0, 5 respectively into the f(x) function.

Thus, we have

f(-1):

[tex]\begin{gathered} f(-1)=2(-1)+1=-2+1 \\ \Rightarrow f(-1)=-1 \end{gathered}[/tex]

f(0):

[tex]\begin{gathered} f(0)=2(0)+1=0+1 \\ \Rightarrow f(0)=1 \end{gathered}[/tex]

f(5):

[tex]\begin{gathered} f(5)=2(5)+1=10+1 \\ \Rightarrow f(5)=11 \end{gathered}[/tex]

To find f(x-1), we substitute (x-1) for x into the f(x) function.

Thus,

[tex]\begin{gathered} f(x-1)=2(x-1)+1 \\ open\text{ parentheses,} \\ 2x-2+1 \\ simplify, \\ \Rightarrow f(x-1)=2x-1 \end{gathered}[/tex]

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