Answered

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Two capacitors having values of 10 μF each are connected in parallel and then hooked up to a 9.0 V battery. How much energy must the battery supply to charge the capacitors?Group of answer choices9.0x10-5 J8.1x10-4 J2.3x10-5 J1.6x10-3 J2.0x10-4 J

Sagot :

Given,

Two capacitors having values of 10 μF each are connected in parallel.

They are then connected to a 9.0 V battery.

The equivalent capacitance is:

[tex]C=10\mu F+10\mu F=20\mu F[/tex]

Thus the energy is equal to,

[tex]\begin{gathered} U=\frac{1}{2}CV^2 \\ \Rightarrow U=\frac{1}{2}\times(20\times10^{-6})\times9^2 \\ \Rightarrow U=8.1\times10^{-4}J \end{gathered}[/tex]

The answer is

[tex]8.1\times10^{-4}J[/tex]

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