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Sagot :
We have to use the distace between points formula to calculate the distance on each case.
Case 1: From Building 1 (-5,-3) to building 2 (-5,5)
[tex]d=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex][tex]d=\sqrt[]{(-5-(-5))^2+(5-(-3)^2}\text{ = 8}[/tex]Case 2: From Building 2 (-5,5) to building 3 (4, 5)
[tex]d=\sqrt[]{(5-5)^2+(4-(-5))^2}\text{ = }9[/tex]Case 3: From Building 3 (4, 5) to building 4 (4, - 3)
[tex]d=\sqrt[]{(-3-5)^2+(4-4)^2}\text{ = }8[/tex]Case 4: From Building 4 (4, - 3) to building 1 (-5,-3)
[tex]d=\sqrt[]{(-3-(-3))^2+(-5-4)^2}\text{ = }9[/tex]The sum of the distances is: 8+9+8+9= 34. And since one unit equals 100 feet. Then the distance biked is 3400 feet.
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