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Where is the value of x Given of x given that PQ=BC

Where Is The Value Of X Given Of X Given That PQBC class=

Sagot :

8

Explanation

here we have 2 congruent triangles

APQ and ABC

as the proportion is the same(red length over blue length)

[tex]\begin{gathered} \frac{x}{12}=\frac{(12+x)}{30} \\ \text{cross multiply} \\ 30\cdot x=(12+x)\cdot12 \\ 30x=144+12x \\ \text{subtract 12 x in both sides} \\ 30x-12x=144+12x-12x \\ 18x=144 \\ \text{divide both sides by 18} \\ \frac{18x}{18}=\frac{144}{18} \\ x=8 \end{gathered}[/tex]

I hope this helps you

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