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Sagot :
[tex]37.5+6x\leq70\rightarrow inequality[/tex]
therefore, the maximum number of foils Justin can have is 5
Explanation
Step 1
set the ineequality
Let x represents the number of foils
and
fee : $ 37.50
rate per foil = $ 6 per foil
total : no more than 70 ( so 70 or smaller)
so
total = fee+ ( cost of foils)
the cost of foils can be calculated using
cot of foils= rate*number of foils
replace
cost of foils= 6x
so, the total cost is
total = fee+ ( cost of foils)
total = 37.5+ 6x
[tex]total=37.5+6x[/tex]but, remember the total must be equal or smaller than 70
henc e
[tex]37.5+6x\leq70\rightarrow inequality[/tex]
Step 2
now, let's solve the inequality
[tex]\begin{gathered} 37.5+6x\leq70\rightarrow inequality \\ \text{subtract 37.5 in both sides} \\ 37.5+6x-37.5\leq70-37.5 \\ 6x\leq32.5 \\ \text{divide both sides by 6} \\ \frac{6x}{6}\leq\frac{32.5}{6} \\ x\leq5.41 \end{gathered}[/tex]as the unit is per foil, we need to use whole numbers, so the answer is
[tex]\begin{gathered} x\leq5.41 \\ x\leq5 \end{gathered}[/tex]therefore, the maximum number of foils Justin can have is 5
I hope this helps you
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