Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The joules of heat released by the metal will be the same that the ones received by the water.
To find the joules that the water received, use the following formula:
[tex]Q=mCp(T2-T1)[/tex]Where Q is the heat released or absorbed, m is the mass, Cp is the specific heat and T2 and T1 are the final and initial temperatures:
The value of Cp for water is 4.18J/g°C, the mass can be found using the density of water which is 1g/mL and T2 and T1 are given:
[tex]m=100.0mL\cdot\frac{1g}{mL}=100.0g[/tex][tex]\begin{gathered} Q=100.0g\cdot\frac{4.18J}{g\degree C}\cdot(30.3\degree C-28.1\degree C) \\ Q=919.6J \end{gathered}[/tex]It means that 919.6 joules of heat are released by the metal.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
