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Sagot :
Explanation:
The Claus reactions are:
2 H₂S + 3 O₂ -----> 2 SO₂ + 2 H₂O
SO₂ + 2 H₂S -----> 3 S + 2 H₂O
First the mass of O₂ must be converted into moles using the molar mass of O₂.
atomic mass of O = 16.00 amu
molar mass of O₂ = 2 * 16.00 g/mol
molar mass of O₂ = 32.00 g/mol
moles of O₂ = mass of O₂/molar mass of O₂
moles of O₂ = 23.0 g/32.00 g/mol
moles of O₂ = 0.719 moles
According to the first reaction, 2 moles of H₂S will react with 3 moles of O₂ to give 2 moles of SO₂ and 2 moles of H₂O. Then, the mole ratio between O₂ and SO₂ is 3 to 2. That relationship can be used to get the number of moles of SO₂ produced by 0.719 moles of O₂. We select SO₂ because it is one of the reactants of the second reaction and it can link both reactions.
2 moles of SO₂ = 3 moles of O₂
moles of SO₂ = 0.719 moles of O₂ * 2 moles of SO₂/(3 moles of O₂)
moles of SO₂ = 0.479 moles
According to the second equation 3 moles of S can be produced by 1 mol of SO₂. That relationship can be used to find the number of moles of S produceeb by 0.479 moles of SO₂.
1 mol of SO₂ = 3 moles of S
moles of S = 0.479 moles of SO₂ * 3 moles of S/(1 mol of SO₂)
moles of S = 1.44 moles
Finally the moles of S produced can be converted back to grams using the molar mass of S.
atomic mass of S = 32.07 amu
molar mass of S = 32.07 g/mol
mass of S = moles of S * molar mass of S
mass of S = 1.44 moles * 32.07 g/mol
mass of S = 46.2 g
Answer: 46.2 g of sulfur is produced from 23.0 grams of oxygen.
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