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Sagot :
Given:
We get two points from the table of car A are (15,1) and (75,5).
We get two points from the table of car B are (45,1) and (180,4).
Required:
We need to determine which car is traveling at the greatest speed and by how much.
Explanation:
Consider the formula to find the speed of the car.
[tex]Speed=\frac{distance}{time}[/tex]Consider the point (15,1).
Substitute distance =15 and time =1 in the formula to find the speed of car A.
[tex]Speed\text{ of car A}=\frac{15}{1}[/tex][tex]Speed\text{ of car A}=15miles\text{ per hour}[/tex]Consider the point (45,1).
Substitute distance =45 and time =1 in the formula to find the speed of car B.
[tex]Speed\text{ of car B}=\frac{45}{1}[/tex][tex]Speed\text{ of car B}=45miles\text{ per hour}[/tex][tex]\text{We know that }45>15.[/tex]The speed of car B is the greatest speed.
Subtract 45 from 15, we get
[tex]45-15=30\text{ miles per hour.}[/tex]The speed of car B is 30 miles per hour greater than car A.
Final answer:
The speed of car B is the greatest speed.
The speed of car B is 30 miles per hour greater than car A.
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