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Sagot :
We can use substitution method to solve this equation.
Given
5x + y = 7 ---------------------------------------------------------- Equation 1
20x + 2 = y ---------------------------------------------------------- Equation 2
We can substitute Equation 2 into Equation 1, thus, we have:
[tex]\begin{gathered} 5x+y=7 \\ 5x+(20x+2)=7 \\ 5x+20x+2=7 \end{gathered}[/tex]Now, we have an equation in x. We can do algebra and solve for x. Shown below:
[tex]\begin{gathered} 5x+20x+2=7 \\ 25x=5 \\ x=\frac{5}{25} \\ x=\frac{1}{5} \end{gathered}[/tex]Now, we use this value of x and substitute into equation 2 to find the value of y. Shown below:
[tex]\begin{gathered} y=20x+2 \\ y=20(\frac{1}{5})+2 \\ y=4+2 \\ y=6 \end{gathered}[/tex]Final solution:
[tex]x=\frac{1}{5},y=6[/tex]
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