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Sagot :
To solve the given equation, it is necessary to factor the expression, this way:
[tex]\begin{gathered} x^2-x-30=0 \\ (x-6)(x+5)=0 \end{gathered}[/tex]Now, for that product to be 0, one of the factor must be 0. It means:
[tex]\begin{gathered} x-6=0 \\ x=6 \\ x+5=0 \\ x=-5 \end{gathered}[/tex]The answer is b. x=-5 and x=6.
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