Answered

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i need help please ..

Sagot :

Answer: y = -3x + 1

Slope-point form:

[tex]y+5=-3(x-2)[/tex]

Let us simplify the equation to form the slope-intercept form of the equation of the line.

[tex]\begin{gathered} y+5=-3(x-2) \\ y+5=-3x+6 \\ y=-3x+6-5 \\ y=-3x+1 \end{gathered}[/tex]

Therefore, its slope-intercept form is y = -3x + 1.

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