At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
We know that the total cost is $1700 and the total work hours are 15.
We will call x the number of hours worked by the first mechanic and y the number of worked hours by the second mechanic.
The total work hours is the sum of x and y and equal to 15:
[tex]x+y=15[/tex]The cost of each mechanic is the price per hour multiplied by the work hours, so we can write:
[tex]115\cdot x+110\cdot y=1700[/tex]We have a system of linear equations.
We will solve it by substitution.
[tex]x+y=15\longrightarrow y=15-x[/tex][tex]\begin{gathered} 115x+110y=1700 \\ 115x+110(15-x)=1700 \\ 115x+1650-110x=1700 \\ 115x-110x=1700-1650 \\ 5x=50 \\ x=\frac{50}{5} \\ x=10 \end{gathered}[/tex][tex]y=15-x=15-10=5[/tex]Answer: the first mechanic worked 10 hours and the second mechanic worked 5 hours.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
