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Sagot :
The belt buckle is shown as comprising of a rectangle and two triangles.
The rectangle has dimensions, 3 inches by 1.5 inches. The triangle has dimensions 1.5 inches (base) by 1.5 inches (vertical height).
The area of the rectangular portion is;
[tex]\begin{gathered} A=l\times w \\ A=3\times1.5 \\ A=4.5in^2 \end{gathered}[/tex]The area of the triangular portion is;
[tex]\begin{gathered} A=\frac{1}{2}b\times h \\ A=\frac{1}{2}\times1.5\times1.5 \\ A=\frac{1}{2}\times2.25 \\ \text{For the area of both triangles it now becomes;} \\ 2A=2(\frac{1}{2}\times2.25) \\ 2A=2.25in^2 \end{gathered}[/tex]The total area of the belt buckle is therefore,
Area = 4.5 + 2.25
Area = 6.75 inches squared
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