Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Solve the following system:2x-6y=-12x+2y=14

Sagot :

We can solve this system by elimination method.

If we multiply by -2 the second equation, we have

[tex]-2x-4y=-28[/tex]

Then, we need to solve the following equivalent system:

[tex]\begin{gathered} 2x-6y=-12 \\ -2x-4y=-28 \end{gathered}[/tex]

Now, we can see that if we add both equations, we obtain

[tex]-6y-4y=-12-28[/tex]

because 2x-2x=0. Then, we have

[tex]\begin{gathered} -10y=-40 \\ y=\frac{-40}{-10} \\ y=4 \end{gathered}[/tex]

Now, we can substitute this result into the first equation. It yields,

[tex]2x-6(4)=-12[/tex]

which gives

[tex]\begin{gathered} 2x-24=-12 \\ 2x=-12+24 \\ 2x=12 \\ x=\frac{12}{2} \\ x=6 \end{gathered}[/tex]

Therefore, the solution is x=6 and y=4.

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.