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Sagot :
SOLUTION
We are given that the Area of the Trapezoid =
[tex]\begin{gathered} A\text{ = }\frac{h\text{ }}{2}(t+b)\text{ } \\ \text{where h = height } \\ t\text{ , b are the parallel sides} \end{gathered}[/tex]Step 1 : Find A if t = 17, b = 33 and h = 14.
[tex]\begin{gathered} A\text{ = }\frac{14}{2}(\text{ 17 + 33 )} \\ \text{ = 7 ( 50 ) } \\ \text{ = 350 square units.} \end{gathered}[/tex]Step 2 : Find A if h = 16.3, t = 15.7 and b = 19.6
[tex]\begin{gathered} A\text{ = }\frac{16.\text{ 3}}{2}\text{ ( 15.7 + 19.6 )} \\ =\text{ }\frac{16.3}{2}\text{ ( 35.3)} \\ =\text{ 287. 695 square units} \end{gathered}[/tex]Step 3 : Find h if A = 72, t = 7, and b = 9
[tex]\begin{gathered} A\text{ = }\frac{h}{2}\text{ ( t + b )} \\ 2\text{ A = h ( t + b ) } \\ h\text{ = }\frac{2A\text{ }}{t\text{ + b}} \\ h\text{ = }\frac{2\text{ X 72}}{7\text{ + 9}} \\ h\text{ = }\frac{144}{16} \\ h\text{ = 9} \end{gathered}[/tex]
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