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Sagot :
Answer:
[tex]\begin{equation*} 64y^2-80y+25 \end{equation*}[/tex]Given:
[tex](8y-5)^2[/tex]When squaring a binomial, we can take note of the following:
[tex](a+b)^2=a^2+2ab+b^2[/tex]From the given, we know that:
a = 8y
b = -5
With these, we have:
[tex]\begin{gathered} (8y-5)^{2} \\ \Rightarrow(8y)^2+(2(8y)(-5))+(-5)^2 \\ \Rightarrow64y^2-80y+25 \end{gathered}[/tex]Therefore,
[tex](8y-5)^2=64y^2-80y+25[/tex]
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