Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
If we have two perpendicular lines of slopes m₁ and m₂, then we have the following equation:
[tex]m_1\cdot m_2=-1\ldots(1)[/tex]From the problem, we have the line with equation 9x - 8y = 10. The slope-intercept form of this line is:
[tex]\begin{gathered} 9x-8y=10 \\ 8y=9x-10 \\ \Rightarrow y=\frac{9}{8}x-\frac{5}{4} \end{gathered}[/tex]Then, the slope of this line is:
[tex]m_1=\frac{9}{8}[/tex]Using (1), we can find the slope of any perpendicular line to this line. Then:
[tex]\begin{gathered} \frac{9}{8}\cdot m_2=-1 \\ \Rightarrow m_2=-\frac{8}{9} \end{gathered}[/tex]Additionally, we know that this line passes through the point (0, 0), so the point-slope form of the perpendicular line is:
[tex]y-0=-\frac{8}{9}(x-0)[/tex]And the corresponding slope-intercept form is:
[tex]y=-\frac{8}{9}x[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
