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Sagot :
Explanation:
Before we solve the problem we have to balance the given equation.
__ Mn₃N₄ + __ NaCl ---> __ MnCl₄ + __ Na₃N
The first step to balance this equation is to determine the number of atoms of each element that we have on both sides of the equation.
__ Mn₃N₄ + __ NaCl ---> __ MnCl₄ + __ Na₃N
Mn = 3 Mn = 1
N = 4 N = 1
Na = 1 Na = 3
Cl = 1 Cl =5
We have 3 atoms of Mn on the left side of the equation and just 1 atom of Mn on the right side. We can change the coefficient for MnCl₄ and write a 3 there to alance the Mn agtoms.
__ Mn₃N₄ + __ NaCl ---> 3 MnCl₄ + __ Na₃N
Mn = 3 Mn = 3
N = 4 N = 1
Na = 1 Na = 3
Cl = 1 Cl = 12
We have 4 atoms of N on the left and 1 on the right side of the equation. We can change the coefficient for N and write a 4 there.
__ Mn₃N₄ + __ NaCl ---> 3 MnCl₄ + 4 Na₃N
Mn = 3 Mn = 3
N = 4 N = 4
Na = 1 Na = 12
Cl = 1 Cl = 12
And finally we hav 12 atoms of Na Aand Cl on the right side of the equation and just 1 atom of them on the left. If we write a 12 in front of NaCl we will balance the equation.
__ Mn₃N₄ + 12 NaCl ---> 3 MnCl₄ + 4 Na₃N
Mn = 3 Mn = 3
N = 4 N = 4
Na = 12 Na = 12
Cl = 12 Cl = 12
The balanced equaton is:
Mn₃N₄ + 12 NaCl ---> 3 MnCl₄ + 4 Na₃N
According to the coefficients of the equation, when 1 mol of Mn₃N₄ reacts with 12 moles of NaCl, 3 moles of MnCl₄ and 4 moles of Na₃N are produced.
So, 12 moles of NaCl will yield 3 moles of MnCl₄.
Answer: 3 moles of MnCl₄ willproduced by 12 moles of NAaCl.
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