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Hello could you please help me with this problem? Write the standard form of the equation y+4=-12/7(x-1).

Sagot :

Given:

[tex]y+4=-\frac{12}{7}\mleft(x-1\mright)[/tex]

express the equation in standard form,

[tex]\begin{gathered} y+4=-\frac{12}{7}(x-1) \\ 7(y+4)=-12(x-1) \\ 7y+28=-12x+12 \\ 7y+12x=12-28 \\ 12x+7y=-16 \end{gathered}[/tex]

Answer:

[tex]12x+7y=-16[/tex]

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