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A 5.00 cm tall object is placed 2.7 cm in front of a concave mirror and produces a real image that is 14.3 cm from the mirror. What is the magnification of the object?

Sagot :

We are asked to determine the magnification of a concave mirror. To do that we will use the following formula:

[tex]M=\frac{h_i}{h_0}=-\frac{d_i}{d__0}[/tex]

Where:

[tex]\begin{gathered} M=\text{ magnification} \\ h_0=\text{ height of the object} \\ h_i=\text{ height of the image} \\ d_0=\text{ distance of the object } \\ di=\text{ distance of the image} \end{gathered}[/tex]

We are given the following values:

[tex]\begin{gathered} h_0=5cm \\ d_0=2.7cm \\ h_i=14.3cm \end{gathered}[/tex]

Therefore, we can use the following to determine the magnification:

[tex]M=\frac{h_i}{h_0}[/tex]

Substituting the values:

[tex]M=\frac{14.3cm}{5cm}[/tex]

Solving the operation:

[tex]M=2.86[/tex]

Therefore, the magnification is 2.86