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If you have 1 points spread out randomly so that no 3 points are colinear, how many lines can you draw using 2 points? (Hint start at 1 dot and connect lines as you add each dot, you might notice a pattern)

If You Have 1 Points Spread Out Randomly So That No 3 Points Are Colinear How Many Lines Can You Draw Using 2 Points Hint Start At 1 Dot And Connect Lines As Yo class=

Sagot :

Solution:

Given that;

If you have 1 point spread out randomly, so that no 3 points are colinear

Colinear points are points that lines on the same line.

Drawing points randomly from the given 3 points

Applying the combination formula,

[tex]\begin{gathered} nCr=\frac{n!}{\left(n-r\right)!r!} \\ Where \\ n=3 \\ r=2 \\ 3C2=\frac{3!}{2!(3-2)!}=\frac{3!}{2!1!}=\frac{3\times2\times1}{2\times1\times1}=3 \end{gathered}[/tex]

Hence, the number of lines you can draw is 3

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