Answered

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Hi, can you help me to solve this exercise please!!!

Hi Can You Help Me To Solve This Exercise Please class=

Sagot :

Given:

[tex]\sin \theta=\frac{12}{13}[/tex]

For given interval:

[tex]\begin{gathered} 90^{\circ}<\theta>180^{\circ} \\ \sin \theta=\frac{12}{13} \\ \theta=\sin ^{-1}(\frac{12}{13}) \\ \text{for interval} \\ \theta=180-\sin ^{-1}(\frac{12}{13}) \\ \theta=180-67.3801 \\ \theta=112.619 \end{gathered}[/tex]

so

[tex]\begin{gathered} =\cos \theta \\ =\cos (112.619) \\ =-0.3846 \end{gathered}[/tex]

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